AQA Jun 2012 Paper 2 Q7 (with explained solutions) |

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AQA Jun 2012 Paper 2 Q7

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do not write outside the box alkenes are useful intermediates in the synthesis of organic compounds a i complete the elimination mechanism by drawing appropriate curly arrows ho h h h ch c c c ch ch ch ch ch chch ch h o br h h br bromohexane hex ene a ii draw structures for the e and z stereoisomers of hex ene e isomer of hex ene z isomer of hex ene marks marks a iii state the meaning of the term stereoisomers marks extra space wmp jun chem do not write outside the box b the equation for the first reaction in the conversion of hex ene into hexan ol is shown below ch ch ch chch ch h so ch ch ch ch oso oh ch ch outline a mechanism for this reaction marks turn over for the next question turn over wmp jun chem

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mark scheme general certificate of education a level chemistry unit chemistry in action june question a i marking guidance mark comments penalise one mark from their total if half headed arrows are used penalise m for formal charge on c of the c br or incorrect partial charges on c br ignore other partial charges penalise once only in any part of the mechanism for a line and two dots to show a bond m must show an arrow from the lone pair on oxygen of a negatively charged hydroxide ion to the correct h atom m must show an arrow from the correct c h bond to the correct c c bond only award if an arrow is shown attacking the h atom of the correct c h bond in m m is independent but ce if nucleophilic substitution n b these are double headed arrows a ii m e isomer award mark if both correct stereoisomers but in the wrong places accept no other alkenes be reasonably lenient on the bonds to ethyl or to ch ch since the question is about e and z positions but penalise once only if connection is clearly to the ch of ch ch accept linear structures m z isomer mark scheme general certificate of education a level chemistry unit chemistry in action june a iii m compounds molecules with the same structural formula m with atoms bonds groups arranged differently in space or atoms bonds groups that have different spatial arrangements different orientation b m must show an arrow from the double bond towards the h atom of the h o bond or ho on a compound with molecular formula for h so m could be to an h ion and m an independent o h bond break on a compound with molecular formula for h so m must show the breaking of the o h bond m is for the structure of the carbocation m must show an arrow from the lone pair of electrons on the correct oxygen of the negatively charged ion towards a correct positively charged carbon atom nb the arrows here are double headed penalise m if same structure ignore references to same molecular formula or same empirical formula or any reference to displayed formula mark independently m ignore partial negative charge on the double bond m penalise partial charges on o h bond if wrong way and penalise formal charges in m do not penalise incorrect structures for h so m not hso for m credit as shown or oso h only with the negative charge anywhere on this ion or correctly drawn out with the negative charge placed correctly on oxygen penalise once only in any part of the mechanism for a line and two dots to show a bond max of any marks for wrong organic reactant or wrong organic product if shown accept the correct use of sticks

Question 1 2 3 4 5 6 7 8 9

Topics to revise

AQA > Inorganic chemistry > Periodicity AS >

1 Periodicity

AQA > Organic Chemistry > Optical isomerism >

1 Optical isomerism

AQA > Organic Chemistry > Organic synthesis >

1 Summary of reactions

AQA > Organic Chemistry > Alkenes AS >

3 Electrophilic addition

AQA > Organic Chemistry > Amino Acids, Proteins and DNA >

5 DNA

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