Edexcel Jun 2009 Paper 1 Q24

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24 Propanone, C3H6O, undergoes complete combustion to form carbon dioxide and water. C3H6O(l) + 4O2(g)3CO2(g) + 3H2O(l) (a) In an experiment to calculate the enthalpy change of combustion for propanone, 2.90 g of propanone was burned completely in oxygen. The heat energy from this combustion raised the temperature of 200 g of water from 20.2 C to 78.4 C. The specific heat capacity of water is 4.18 J g1C1. (i) Calculate the number of moles of propanone present in 2.90 g. [The molar mass of propanone is 58 g mol1.] (1) (ii) Use the expression energy transferred (J) = massspecific heat capacity temperature change to calculate the heat energy transferred to raise the temperature of 200 g of water from 20.2 C to 78.4 C. (2) (iii) Use your answers to (a)(i) and (ii) to calculate a value for the enthalpy change of combustion of propanone. Give your answer to three significant figures and include a sign and units. (3) *H34471A02328* 23 Turn over<br />
 (b) In another experiment, the enthalpy change of combustion for butanone, C4H8O, was found to be 1300 kJ mol1. A Data Book value for the standard enthalpy change of combustion for butanone is 2440 kJ mol1. (i) Suggest a reason why the value obtained in the experiment is so different from the Data Book value. (1)(ii) This Data Book value (2440 kJ mol1) refers to the following equation. C4H8O(l) + 1O2(g)4CO2(g) + 4H2O(l) How would the value be different if it referred to the formation of water in the gaseous state? Justify your answer. (2) DifferenceJustification(c) Standard enthalpy changes of combustion can be used to calculate the standard enthalpy change of formation of a compound. (i) Define the term standard enthalpy change of formation, making clear the meaning of standard in this context. (3)24 *H34471A02428*<br />
 (ii) Use the standard enthalpy changes of combustion, Hc , given in the table below to find the standard enthalpy change of formation for ethanoic acid, CH3COOH, in kJ mol1. Substance C(s, graphite) H2(g) CH3COOH(l) Hc / kJ mol1 394 286 870 2C(s, graphite) + 2H2(g) + O2(g)CH3COOH(l) (3) (Total for Question 24 = 15 marks) TOTAL FOR SECTION B = 60 MARKS TOTAL FOR PAPER = 80 MARKS *H34471A02528* 25<br />

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