Edexcel Jan 2015 (IAL) Paper 4 Q23

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23 Ethanoic acid, CH3COOH, is a weak acid found in vinegar. Successive replacement of the methyl hydrogen atoms by chlorine atoms gives chloroethanoic acid, CH2ClCOOH dichloroethanoic acid, CHCl2COOH trichloroethanoic acid, CCl3COOH (a) (i) Explain the term weak acid. (2) WeakAcid(ii) Write the expression for the acid dissociation constant, Ka, of dichloroethanoic acid, CHCl2COOH. (iii) Use the Ka data from page 18 in the Data Booklet to place the four acids, named in the introduction to the question, in order of increasing strength. State how the order that you have given can be deduced from the Ka data. weakest acidstrongest acidReason (1) (2)18 *P45044A01828*<br />
 (b) (i) Calculate the pH of a solution of 0.10 mol dm3 ethanoic acid. State clearly any assumptions you have made. (4) Assumptions*P45044A01928* 19 Turn over<br />
 (ii) Draw the titration curve, showing the change in pH when 0.10 mol dm3 sodium hydroxide solution is added to 25 cm3 of 0.10 mol dm3 ethanoic acid, until 40 cm3 of sodium hydroxide has been added. (4) 1413121110pH 98765432100 10 15 25 Volume of NaOH(aq) / cm3 20 *(iii) Select a suitable indicator for this titration. Justify your selection. 30 35 40 (2)20 *P45044A02028*<br />
 (c) Ethanoic acid and trichloroethanoic acid react together in an acid-base reaction. Complete the equation by writing the formulae of the acid and base produced in this reaction. Identify the conjugate acid-base pairs in the spaces under the formulae. (2) CH3COOH + CCl3COOH (cid:111)+(Total for Question 23 = 17 marks) TOTAL FOR SECTION B = 47 MARKS *P45044A02128* 21 Turn over<br />

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