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CIE Nov 2015 v3 Paper 2 Q1
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![Answer all the questions in the spaces provided. PMT Aluminium is a metal in Period 3 and Group III of the Periodic Table. (a) Describe the structure of solid aluminium.[2] (b) A common use of aluminium is to make the conducting cables in long distance overhead power lines. (i) Suggest two properties of aluminium that make it suitable for this use.[2] The cables are attached to pylons by ceramic supports. (ii) Describe the structure of a ceramic material.[1] (iii) State the property of a ceramic material that makes it suitable for this use.[1]UCLES 2015 9701/23/O/N/15<br />
PMT (c) Aluminium reacts with chlorine to form a white, solid chloride that contains 79.7% chlorine and sublimes (changes straight from a solid to a gas) at 180 C. (i) Describe the structure and bonding in this compound. Suggest how it explains the low sublimation temperature.[2] (ii) Calculate the empirical formula of the chloride. You must show your working. empirical formula =[2] At 200 C and 100 kPa, a 1.36 g sample of this chloride occupied a volume of 200 cm3. (iii) Calculate the relative molecular mass, Mr, of the chloride. Give your answer to three signi cantgures. (iv) Deduce the molecular formula of this chloride at 200 C.[1] Mr =[2] [Total: 13]UCLES 2015 9701/23/O/N/15 [Turn over<br />](https://learnah.org/wp-content/uploads/2018/08/November_2015_v3_QP_-_Paper_2_CIE_Chemistry_A-level_1-0.jpg)
![Page 2 Mark Scheme Syllabus Paper Cambridge International AS/A LevelOctober/November 2015 9701 23 Question Mark Scheme (a) regular arrangement / lattice of cations / positive ions surrounded by delocalised electrons (b) (i) electrical conductor corrosion resistant low density ductile owtte (ii) Giant / lattice (iii) (electrical) insulator (c) (i) Simple covalent / covalent molecule Weak intermolecular forces / VdW forces OR little energy needed to break down / overcome intermolecular / VdW forces (ii) Al Cl 20.3 79.7 27 35.5 0.752 2.25 0.752 0.752 AlClCambridge International Examinations 2015 PMT Mark Total [1] [1] [1] [1] [2] [max2] [1] [1] [1] [1] [2] [2] [1] [1] [1] [1]<br />
Page 3 Mark Scheme Syllabus Paper Cambridge International AS/A LevelOctober/November 2015 9701 23 PMT Question Mark Scheme (iii) pV RT OR pV = nRT (iv) Al2Cl mRT 1.36 8.31 473 M = pV 100 10 200 10 = 267 pV n = RT 1001020010 6 8.31473 5.09 = 10 1.36 5.09 10 267 (a) (i) The enthalpy change when one mole of a compound is formed from its element(s) (ii) S(s) + 1O2(g)SO3(l) (b) (i) 944 + (3436) = 2252 6390 = 2340 22522340 = 88 (kJ mol (ii) Fe catalyst 200 atm 400500 ()C (iii) High T increases rate AND Low T improves yield owtte Chosen temp is a compromise High P favours / increases (both rate and) yield owtte pressure chosen limited by cost (of compression and thick walls)Cambridge International Examinations 2015 Mark Total [1] [1] [1] [1] [2] [1] [1] [13] [1] [1] [2] [1] [1] [1] [1] [1] [1] [1] [1] [1] [1] [1] [1] [3] [3] [4]<br />](https://learnah.org/wp-content/uploads/2018/08/November_2015_v3_MS_-_Paper_2_CIE_Chemistry_A-level_1-0.jpg)
