AQA Jun 2017 Paper 1 Q5 (with explained solutions) |

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AQA Jun 2017 Paper 1 Q5

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0 5 0 5 . 1 *10* 10 Titanium(IV) chloride can be made from titanium(IV) oxide as shown in the equation. TiO2(s) + 2C(s) + 2Cl2 (g)2CO(g) + TiCl4(l) Ho = 60.0 kJ mol1 Some entropy data are shown in Table 3. Table 3Substance So / J K1 mol1 TiO2(s) 50.2 C(s) 5.70 Cl2(g) 223 CO(g) 198 TiCl4(l) 253 Use the equation and the data in Table 3 to calculate the Gibbs free-energy change for this reaction at 989 C Give your answer to the appropriate number of significant figures. Use your answer to explain whether this reaction is feasible. [6 marks] Explanation Gibbs free-energy change kJ mol1 IB/M/Jun17/7405/1<br />
11 Turn over for the next questionDO NOT WRITE ON THIS PAGE ANSWER IN THE SPACES PROVIDED *11* Turn overIB/M/Jun17/7405/1<br />

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MARK SCHEMEA-LEVEL CHEMISTRY7405/1JUNE 2017 Question Answers Mark Additional Comments/Guidance S = S productsS reactants or 253 + (2 x 198)( 2 x 223 + 2 x 5.7 + 50.2) (= 649507.6)S = 141(.4) (J K1mol1) G = H - TS 05.1 G = -60 - (1262 x 141(.4) x 10-3) = 238 (kJ mol1 ) to 3 sig figs feasible since G is negative/less than zero Total This expression could also score M1 This scores M1 and M2 Allow ecf for M3, M4 and M5 from incorrect M2 This expression also scores M3. For M4, allow G = -60 - (1262 x their M2 x 10-3) If calculated in joules M4: Allow G = -60x103 - (1262 x 141(.4)) M5: Allow -238 000 J mol1 providing units shown Allow consequential M6 from their G 22 of 35<br />

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