OCR A Jun 2017 Paper 2 Q5

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11 5 Propanoic acid, CH3CH2COOH, is a member of the homologous series of carboxylic acids. (a) Suggest the general formula for a carboxylic acid.[1] (b) The displayed formula for propanoic acid is shown below. (i) State the shape and bond angle around a carbon atom in the alkyl group of propanoic acid. Explain the shape. ShapeBond angleExplanation[2] (ii) Suggest a value for the COH bond angle in propanoic acid.[1]<br />
 12 (c) Compound D is a neutral compound which is a structural isomer of propanoic acid, CH3CH2COOH. The infrared spectrum of compound D is shown below. Suggest two possible structures of compound D. Explain all your reasoning.[4]<br />
 (d) 2-Chloropropanoic acid, CH3CHClCOOH, can be made by reacting propanoic acid with 13 chlorine in a radical substitution reaction. (i) State the conditions for the reaction.[1] (ii) Write the overall equation for the reaction.[1] (iii) The first step in the reaction mechanism involves homolytic fission of a chlorine molecule to form two chlorine radicals. Why is this step an example of homolytic fission?[1] (iv) Write two equations to show the propagation steps in the mechanism for this reaction. Use dots,, to show the unpaired electrons on radicals.[2] (v) Draw the displayed formula of the radical formed in the first propagation step. Use a dot,, to show the position of the unpaired electron. (vi) Further substitution forms a mixture of organic products. Draw the structure of an organic product formed from 2-chloropropanoic acid by further substitution. [1] [1]<br />

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