Edexcel Jun 2013 Paper 1 Q19

Answers available below

19 This question is about the elements arsenic to rubidium which have atomic numbers 33 to 37. The first ionization energies, Em1, of these elements are given in the table. Element Em1 / kJ mol1 As 947 Se 941 Br 1140 Kr 1351 Rb 403 (a) Write the equation, with state symbols, which represents the first ionization energy of arsenic. (b) Suggest the formulae of the hydrides of arsenic and selenium. (c) (i) Complete the electronic configuration for an arsenic and a selenium atom using the electrons-in-boxes notation. As Se [Ar] 3d10 [Ar] 3d10 4s np np 4p (2) (2) (2) 10 *P41649A01024*<br />
 *(ii) Explain why the first ionization energy of selenium is lower than that of arsenic. (2)*(d) Explain why the first ionization energy of krypton is higher than that of selenium. (2)*(e) Explain why the first ionization energy of rubidium is lower than that of krypton. (2)(f) Which of the elements, arsenic to rubidium, is likely to have atoms with the smallest atomic radius? (1)(Total for Question 19 = 13 marks) *P41649A01124* 11 Turn over<br />
 BLANK PAGE 12 *P41649A01224*<br />

Show answer