Edexcel Jun 2013 (R) Paper 1 Q23

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23 Crude oil is a complex mixture of hydrocarbons. Initial separation is achieved by fractional distillation of the crude oil. The separate fractions are further refined to produce hydrocarbons such as decane, C10H22. (a) Give the general formula of alkanes. (b) Carbon monoxide, CO, is formed during the incomplete combustion of decane. (i) Write an equation for the incomplete combustion of decane, forming carbon monoxide and water only. (ii) Explain why incomplete combustion can occur. (1) (1) (1)(c) Low-sulfur fuel is now supplied to petrol stations. The removal of sulfur from diesel and petrol reduces the emission of toxic oxides of sulfur from vehicle exhausts. One such oxide is sulfur dioxide, SO2. The bonding in sulfur dioxide may be represented as shown below. O = S o O Complete the dot and cross diagram below for the SO2 molecule, showing only outer shell electrons. Use dots to represent the oxygen electrons and crosses to represent the sulfur electrons. (3) *P42982A01524* 15 Turn over<br />
 (d) Another alkane produced from crude oil is heptane, C7H16. The reforming of heptane produces methylcyclohexane and only one other product. A methylcyclohexane molecule is made from a ring of six carbon atoms bonded to a methyl group. (i) Use the information given above to give the skeletal formula of methylcyclohexane. (ii) Write a balanced equation, using molecular formulae, for the reforming of heptane into methylcyclohexane and one other product. State symbols are not required. (iii) Suggest a reason why oil companies reform alkanes such as heptane. (1) (1) (1)16 *P42982A01624*<br />
 (e) Five branched-chain isomers of heptane are shown in the boxes below. 2-methylhexane 2,3-dimethylpentane 2,2,3-trimethylbutane 2,4-dimethylpentane isomer A (i) Give the systematic name of isomer A. (1)(ii) In the empty boxes above, draw skeletal formulae for two other branched-chain isomers of C7H16, with no side-chain having more than one carbon atom. (2) *P42982A01724* 17 Turn over<br />
 (f) Butane, C4H10, reacts with chlorine, Cl2, at room temperature and pressure. (i) What other condition is essential for this reaction? C4H10 + Cl2 oC4H9Cl + HCl (1)(ii) Write an equation for the initiation step of the mechanism for the above reaction. Curly arrows are not required. (iii) State the type of bond fission involved in the initiation step. (1) (1)(iv) Write equations for the two propagation steps of this mechanism. Curly arrows are not required. First propagation step: Second propagation step: (v) Write one equation for a reaction that would terminate this mechanism. (2) (1) (Total for Question 23 = 18 marks) 18 *P42982A01824*<br />

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